scanf string in python

lehrig wrote:

I have a string which is returned by a C extension.

mystring = '(1,2,3)'

HOW can I read the numbers in python ?

re.findall seems the safest and easiest solution:

re.findall(r'(\d+)', '(1, 2, 3)') ['1', '2', '3'] map(int, re.findall(r'(\d+)', '(1, 2, 3)'))

[1, 2, 3]

Flavor to taste.

--
Erik Max Francis && ma*@alcyone.com && http://www.alcyone.com/max/
__ San Jose, CA, USA && 37 20 N 121 53 W && &tSftDotIotE
/ \ You can buy any kind of love, but you can't buy love deluxe.
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lehrig wrote:

I have a string which is returned by a C extension.

mystring = '(1,2,3)'

HOW can I read the numbers in python ?

Now I have done it like this:
tmp = mystring[1:-1]
tmplist = string.split(tmp,',')
x = int(tmplist[0])
y = int(tmplist[1])
z = int(tmplist[2])

But there should be a more convenient solution.

lehrig schrieb:

lehrig wrote:

I have a string which is returned by a C extension.

mystring = '(1,2,3)'

HOW can I read the numbers in python ?

Now I have done it like this:
tmp = mystring[1:-1]
tmplist = string.split(tmp,',')
x = int(tmplist[0])
y = int(tmplist[1])
z = int(tmplist[2])

But there should be a more convenient solution.

exec('result='+mystring)
print result

would be shorter

Karl

lehrig wrote:

lehrig wrote:

I have a string which is returned by a C extension.

mystring = '(1,2,3)'

HOW can I read the numbers in python ?

Now I have done it like this:
tmp = mystring[1:-1]
tmplist = string.split(tmp,',')
x = int(tmplist[0])
y = int(tmplist[1])
z = int(tmplist[2])

But there should be a more convenient solution.

Hi,

some have suggested map, exec and re's. I came up with this list
comprehenion

mystring = '(1,2,3)'
mynumbers = [int(i) for i in mystring[1:-1].split(',')]
mynumbers

[1, 2, 3]

regards
Jorgen Cederberg

On Friday 18 Jul 2003 8:39 am, Jørgen Cederberg wrote:

lehrig wrote:

lehrig wrote:

I have a string which is returned by a C extension.

mystring = '(1,2,3)'

HOW can I read the numbers in python ?

Now I have done it like this:
tmp = mystring[1:-1]
tmplist = string.split(tmp,',')
x = int(tmplist[0])
y = int(tmplist[1])
z = int(tmplist[2])

But there should be a more convenient solution.

Hi,

some have suggested map, exec and re's. I came up with this list
comprehenion

>>> mystring = '(1,2,3)'
>>> mynumbers = [int(i) for i in mystring[1:-1].split(',')]
>>> mynumbers
[1, 2, 3]

regards
Jorgen Cederberg

what about:

x,y,z=eval(mystring)

???
see:

x,y,z=eval(mystring)
x,y,z (1, 2, 3) x 1 y 2 z

NOTE: this could introduce exploitable behaviour if you can't guarantee that
the string is *only* going to contain a tuple of nembers... think about what
could happen if the c code returned 'ReallyNastyFunc()' instead of
"(1,2,3)"... :-(. As long as you can guarantee the value won't be
'dangerous' you'll be ok.

hth -ndyj

On Thu, 17 Jul 2003 22:37:07 -0700, Erik Max Francis <ma*@alcyone.com> wrote:

lehrig wrote:

I have a string which is returned by a C extension.

mystring = '(1,2,3)'

HOW can I read the numbers in python ?

re.findall seems the safest and easiest solution:

re.findall(r'(\d+)', '(1, 2, 3)')['1', '2', '3'] map(int, re.findall(r'(\d+)', '(1, 2, 3)'))[1, 2, 3]

Did you use the regex parens for a reason I am unaware of?

import re
re.findall(r'(\d+)', '(1, 2, 3)') ['1', '2', '3'] re.findall(r'\d+', '(1, 2, 3)')

['1', '2', '3']

Regards,
Bengt Richter

Bengt Richter wrote:

Did you use the regex parens for a reason I am unaware of?

>>> import re
>>> re.findall(r'(\d+)', '(1, 2, 3)') ['1', '2', '3'] >>> re.findall(r'\d+', '(1, 2, 3)')

['1', '2', '3']

Habit. In any other context, I'd want to isolate those buggers in a
group, so that's what I wrote that here. I wasn't specifically aware
that they were unnecessary with re.findall.

--
Erik Max Francis && ma*@alcyone.com && http://www.alcyone.com/max/
__ San Jose, CA, USA && 37 20 N 121 53 W && &tSftDotIotE
/ \ I'm sharing the joy / I'm glowing like sunshine
\__/ Chante Moore