hi i want a c program to find the inverse of 3X3 matrix
urgent
i need it
fast
anyoone reply
thanks
1  19794   Banfa 9,065
Recognized Expert Moderator Expert
Here is some visual basic code that does something similar, see if you can convert and adapt it.
Can you describe the process of inverting a matrix? -
Private Function InternalMatrixSolve(ByRef r1() As Double, ByRef r2() As Double, ByVal size%)
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Dim Matrix(2, 2) As Double
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Dim Vector(2) As Double
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Rem Set up the normalised matrix and vector
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For y% = 0 To 2
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For x% = 0 To 2
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Matrix(y%, x%) = 0
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For r% = 1 To size
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Matrix(y%, x%) = Matrix(y%, x%) + ((r1(r%) ^ y%) * (r1(r%) ^ x%))
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Next
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Next
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Vector(y%) = 0
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For r% = 1 To size
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Vector(y%) = Vector(y%) + ((r1(r%) ^ y%) * r2(r%))
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Next
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Next
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For y% = 0 To 2
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Rem Get a 1 on the diagonal by dividing through the current line by the diagnoal cell
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Divisor# = Matrix(y%, y%)
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If Divisor# = 0 Then
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InternalMatrixSolve = "MATHS ERROR"
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Exit Function
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End If
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For x% = y% To 2
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Matrix(y%, x%) = Matrix(y%, x%) / Divisor#
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Next
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Vector(y%) = Vector(y%) / Divisor#
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Rem get 0s below the current diagonal by taking away multiples of the current line
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For y2% = y% + 1 To 2
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Multiplier# = Matrix(y2%, y%)
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For x% = y% To 2
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Matrix(y2%, x%) = Matrix(y2%, x%) - (Matrix(y%, x%) * Multiplier#)
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Next
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Vector(y2%) = Vector(y2%) - (Vector(y%) * Multiplier#)
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Next
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Next
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Rem we now have 1s on the diagnoal and )s below the diagonal
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Rem need to get 0s above the diagonal
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For y% = 2 To 0 Step -1
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Rem get 0s above the current diagonal by taking away multiples of the current line
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For y2% = y% - 1 To 0 Step -1
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Multiplier# = Matrix(y2%, y%)
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For x% = y% To 2
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Matrix(y2%, x%) = Matrix(y2%, x%) - (Matrix(y%, x%) * Multiplier#)
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Next
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Vector(y2%) = Vector(y2%) - (Vector(y%) * Multiplier#)
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Next
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Next
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InternalMatrixSolve = Vector
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End Function
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