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Numbers in words

271 100+
hi friends,
i need a small help. can any one help in converting the numbers entered in a text box to words.

thanks in advance.....
Jan 11 '07 #1
13 2186
hariharanmca
1,977 1GB
hi friends,
i need a small help. can any one help in converting the numbers entered in a text box to words.

thanks in advance.....


'Class ConvertMoney
Private m_19AndUnder(19) As String
Private m_Tens(9) As String
Private m_Hundred As String
Private m_Groups(10) As String
Private m_Dollar As String
Private m_Dollars As String
Private m_NoCents As String
Private m_Cent As String
Private m_Cents As String
Private m_Hyphen As String
Private m_And As String
Private m_InvalidAmount As String


Public Function MonetaryToWords(ByVal Value As Variant) As String
Dim decValue As Double
Dim sValue As String
Dim iDecimal As Integer
Dim sCents As String
Dim sDollars As String
'Convert input into a Decimal value (up to 28 digits)
decValue = CDbl(Value)
If decValue < 0 Then GoTo ER

'Convert the Decimal value back into a string. This eliminates
' any format characters such as "$" or ",".
sValue = CStr(decValue)

'Find the decimal point & extract the dollars from the cents
iDecimal = InStr(1, sValue, ".")
If iDecimal = 0 Then
sDollars = sValue
sCents = "00"
Else
'Extract decimal value
sCents = Mid$(sValue, iDecimal + 1)
If Len(sCents) > 2 Then GoTo ER

'Extract dollars
sDollars = Left$(sValue, iDecimal - 1)

'Fill-out decimal places to two digits
sCents = Left$(sCents & "00", 2)
End If

'At this point,
' sDollars = the whole dollar value (0.. approx 79 Octillion)
' sCents = the cents (00..99)

Debug.Assert (Len(sCents) = 2)
Debug.Assert (Len(sDollars) > 0)
Debug.Assert (Len(sDollars) < 31)

Select Case sCents
Case "00"
sCents = m_NoCents

Case "01"
sCents = sCents & m_Cent

Case Else
sCents = sCents & m_Cents
End Select

MonetaryToWords = DollarsToWords(sDollars) & m_And & sCents

Exit Function

ER:

MonetaryToWords = m_InvalidAmount
End Function



Private Function DollarsToWords(ByVal sDollars As String) As String
Dim sWords As String
Dim decValue As Double
Dim sRemaining As String
Dim s3Digits As String
Dim iGroup As Integer
Dim i100s As Integer
Dim i10s As Integer
Dim i1s As Integer
Dim i99OrLess As Integer
Dim sWork As String

'We had better be passing a valid number
Debug.Assert (IsNumeric(sDollars))

'Check for special cases. This also serves to validate the value
decValue = CDec(sDollars)
Select Case decValue
Case 0
DollarsToWords = m_19AndUnder(decValue) & m_Dollars
Exit Function

Case 1
DollarsToWords = m_19AndUnder(decValue) & m_Dollar
Exit Function

End Select

'There should be no insignificant zeroes, "punctuation" or decimals
Debug.Assert (sDollars = CStr(decValue))

iGroup = 0
sRemaining = sDollars
sWords = ""

'Extract each group of three digits, convert to words and prefix to result
While Len(sRemaining) > 0
iGroup = iGroup + 1

'Extract next group of three digits
If Len(sRemaining) > 3 Then
s3Digits = Right$(sRemaining, 3)
sRemaining = Left$(sRemaining, Len(sRemaining) - 3)
Else
'Fill-out group to three digits
s3Digits = Right$("00" & sRemaining, 3)
sRemaining = ""
End If

Debug.Assert (Len(s3Digits) = 3)

If s3Digits <> "000" Then
i100s = CInt(Left$(s3Digits, 1))
i10s = CInt(Mid$(s3Digits, 2, 1))
i1s = CInt(Right$(s3Digits, 1))
i99OrLess = (i10s * 10) + i1s
sWork = " " & m_Groups(iGroup)

Select Case True
'Do we have 20..99?
Case i10s > 1
Debug.Assert (i10s <= 9)

If i1s > 0 Then
Debug.Assert (i1s <= 9)

sWork = m_Tens(i10s) & m_Hyphen & m_19AndUnder(i1s) & sWork
Else
sWork = m_Tens(i10s) & sWork
End If

'Do we have 01..19?
Case i99OrLess > 0
Debug.Assert (i99OrLess <= 99)

sWork = m_19AndUnder(i99OrLess) & sWork

Case Else
'If we're here, it's because there are no tens or ones
Debug.Assert (i99OrLess = 0)
Debug.Assert (i10s = 0)
Debug.Assert (i1s = 0)
Debug.Assert (Right$(s3Digits, 2) = "00")

'If there's no tens or ones, there better be hundreds
Debug.Assert (i100s > 0)

End Select

If i100s > 0 Then
Debug.Assert (i100s <= 9)

sWork = m_19AndUnder(i100s) & " " & m_Hundred & " " & sWork
End If

Debug.Assert (Len(Trim$(sWork)) > 0)

sWords = sWork & " " & sWords
End If
Wend

DollarsToWords = Trim$(sWords) & m_Dollars
End Function



Private Sub Class_Initialize()
'Initialize all the "words"
m_19AndUnder(0) = "Zero"
m_19AndUnder(1) = "One"
m_19AndUnder(2) = "Two"
m_19AndUnder(3) = "Three"
m_19AndUnder(4) = "Four"
m_19AndUnder(5) = "Five"
m_19AndUnder(6) = "Six"
m_19AndUnder(7) = "Seven"
m_19AndUnder(8) = "Eight"
m_19AndUnder(9) = "Nine"
m_19AndUnder(10) = "Ten"
m_19AndUnder(11) = "Eleven"
m_19AndUnder(12) = "Twelve"
m_19AndUnder(13) = "Thirteen"
m_19AndUnder(14) = "Fourteen"
m_19AndUnder(15) = "Fifteen"
m_19AndUnder(16) = "Sixteen"
m_19AndUnder(17) = "Seventeen"
m_19AndUnder(18) = "Eighteen"
m_19AndUnder(19) = "Nineteen"

m_Tens(2) = "Twenty"
m_Tens(3) = "Thirty"
m_Tens(4) = "Forty"
m_Tens(5) = "Fifty"
m_Tens(6) = "Sixty"
m_Tens(7) = "Seventy"
m_Tens(8) = "Eighty"
m_Tens(9) = "Ninety"

m_Hundred = "Hundred"

m_Groups(1) = ""
m_Groups(2) = "Thousand"
m_Groups(3) = "Million"
m_Groups(4) = "Billion"
m_Groups(5) = "Trillion"
m_Groups(6) = "Quadrillion"
m_Groups(7) = "Quintillion"
m_Groups(8) = "Sextillion"
m_Groups(9) = "Septillion"
m_Groups(10) = "Octillion"

m_Dollar = " Rupee"
m_Dollars = " Rupees"

m_NoCents = "No Paise"
'm_Cent & m_Cents could both be changed to "/100"
m_Cent = " Paise"
m_Cents = " Paise"

'Used for #s like: 23 = "Twenty-Three"
m_Hyphen = "-"

'Used between dollars & cents: "One Dollar and 12 Cents"
m_And = " and "

m_InvalidAmount = "Invalid Rupees Amount."
End Sub
Jan 11 '07 #2
hariharanmca
1,977 1GB
'Class ConvertMoney
Private m_19AndUnder(19) As String
Private m_Tens(9) As String
Private m_Hundred As String
Private m_Groups(10) As String
Private m_Dollar As String
Private m_Dollars As String
Private m_NoCents As String
Private m_Cent As String
Private m_Cents As String
Private m_Hyphen As String
Private m_And As String
Private m_InvalidAmount As String


Public Function MonetaryToWords(ByVal Value As Variant) As String
Dim decValue As Double
Dim sValue As String
Dim iDecimal As Integer
Dim sCents As String
Dim sDollars As String
'Convert input into a Decimal value (up to 28 digits)
decValue = CDbl(Value)
If decValue < 0 Then GoTo ER

'Convert the Decimal value back into a string. This eliminates
' any format characters such as "$" or ",".
sValue = CStr(decValue)

'Find the decimal point & extract the dollars from the cents
iDecimal = InStr(1, sValue, ".")
If iDecimal = 0 Then
sDollars = sValue
sCents = "00"
Else
'Extract decimal value
sCents = Mid$(sValue, iDecimal + 1)
If Len(sCents) > 2 Then GoTo ER

'Extract dollars
sDollars = Left$(sValue, iDecimal - 1)

'Fill-out decimal places to two digits
sCents = Left$(sCents & "00", 2)
End If

'At this point,
' sDollars = the whole dollar value (0.. approx 79 Octillion)
' sCents = the cents (00..99)

Debug.Assert (Len(sCents) = 2)
Debug.Assert (Len(sDollars) > 0)
Debug.Assert (Len(sDollars) < 31)

Select Case sCents
Case "00"
sCents = m_NoCents

Case "01"
sCents = sCents & m_Cent

Case Else
sCents = sCents & m_Cents
End Select

MonetaryToWords = DollarsToWords(sDollars) & m_And & sCents

Exit Function

ER:

MonetaryToWords = m_InvalidAmount
End Function



Private Function DollarsToWords(ByVal sDollars As String) As String
Dim sWords As String
Dim decValue As Double
Dim sRemaining As String
Dim s3Digits As String
Dim iGroup As Integer
Dim i100s As Integer
Dim i10s As Integer
Dim i1s As Integer
Dim i99OrLess As Integer
Dim sWork As String

'We had better be passing a valid number
Debug.Assert (IsNumeric(sDollars))

'Check for special cases. This also serves to validate the value
decValue = CDec(sDollars)
Select Case decValue
Case 0
DollarsToWords = m_19AndUnder(decValue) & m_Dollars
Exit Function

Case 1
DollarsToWords = m_19AndUnder(decValue) & m_Dollar
Exit Function

End Select

'There should be no insignificant zeroes, "punctuation" or decimals
Debug.Assert (sDollars = CStr(decValue))

iGroup = 0
sRemaining = sDollars
sWords = ""

'Extract each group of three digits, convert to words and prefix to result
While Len(sRemaining) > 0
iGroup = iGroup + 1

'Extract next group of three digits
If Len(sRemaining) > 3 Then
s3Digits = Right$(sRemaining, 3)
sRemaining = Left$(sRemaining, Len(sRemaining) - 3)
Else
'Fill-out group to three digits
s3Digits = Right$("00" & sRemaining, 3)
sRemaining = ""
End If

Debug.Assert (Len(s3Digits) = 3)

If s3Digits <> "000" Then
i100s = CInt(Left$(s3Digits, 1))
i10s = CInt(Mid$(s3Digits, 2, 1))
i1s = CInt(Right$(s3Digits, 1))
i99OrLess = (i10s * 10) + i1s
sWork = " " & m_Groups(iGroup)

Select Case True
'Do we have 20..99?
Case i10s > 1
Debug.Assert (i10s <= 9)

If i1s > 0 Then
Debug.Assert (i1s <= 9)

sWork = m_Tens(i10s) & m_Hyphen & m_19AndUnder(i1s) & sWork
Else
sWork = m_Tens(i10s) & sWork
End If

'Do we have 01..19?
Case i99OrLess > 0
Debug.Assert (i99OrLess <= 99)

sWork = m_19AndUnder(i99OrLess) & sWork

Case Else
'If we're here, it's because there are no tens or ones
Debug.Assert (i99OrLess = 0)
Debug.Assert (i10s = 0)
Debug.Assert (i1s = 0)
Debug.Assert (Right$(s3Digits, 2) = "00")

'If there's no tens or ones, there better be hundreds
Debug.Assert (i100s > 0)

End Select

If i100s > 0 Then
Debug.Assert (i100s <= 9)

sWork = m_19AndUnder(i100s) & " " & m_Hundred & " " & sWork
End If

Debug.Assert (Len(Trim$(sWork)) > 0)

sWords = sWork & " " & sWords
End If
Wend

DollarsToWords = Trim$(sWords) & m_Dollars
End Function



Private Sub Class_Initialize()
'Initialize all the "words"
m_19AndUnder(0) = "Zero"
m_19AndUnder(1) = "One"
m_19AndUnder(2) = "Two"
m_19AndUnder(3) = "Three"
m_19AndUnder(4) = "Four"
m_19AndUnder(5) = "Five"
m_19AndUnder(6) = "Six"
m_19AndUnder(7) = "Seven"
m_19AndUnder(8) = "Eight"
m_19AndUnder(9) = "Nine"
m_19AndUnder(10) = "Ten"
m_19AndUnder(11) = "Eleven"
m_19AndUnder(12) = "Twelve"
m_19AndUnder(13) = "Thirteen"
m_19AndUnder(14) = "Fourteen"
m_19AndUnder(15) = "Fifteen"
m_19AndUnder(16) = "Sixteen"
m_19AndUnder(17) = "Seventeen"
m_19AndUnder(18) = "Eighteen"
m_19AndUnder(19) = "Nineteen"

m_Tens(2) = "Twenty"
m_Tens(3) = "Thirty"
m_Tens(4) = "Forty"
m_Tens(5) = "Fifty"
m_Tens(6) = "Sixty"
m_Tens(7) = "Seventy"
m_Tens(8) = "Eighty"
m_Tens(9) = "Ninety"

m_Hundred = "Hundred"

m_Groups(1) = ""
m_Groups(2) = "Thousand"
m_Groups(3) = "Million"
m_Groups(4) = "Billion"
m_Groups(5) = "Trillion"
m_Groups(6) = "Quadrillion"
m_Groups(7) = "Quintillion"
m_Groups(8) = "Sextillion"
m_Groups(9) = "Septillion"
m_Groups(10) = "Octillion"

m_Dollar = " Rupee"
m_Dollars = " Rupees"

m_NoCents = "No Paise"
'm_Cent & m_Cents could both be changed to "/100"
m_Cent = " Paise"
m_Cents = " Paise"

'Used for #s like: 23 = "Twenty-Three"
m_Hyphen = "-"

'Used between dollars & cents: "One Dollar and 12 Cents"
m_And = " and "

m_InvalidAmount = "Invalid Rupees Amount."
End Sub


give value to MonetaryToWords argument it will return string
Jan 11 '07 #3
hariharanmca
1,977 1GB
give value to MonetaryToWords argument it will return string

It's in VB 6 Code
Jan 11 '07 #4
karthi84
271 100+
hi can u get me the same coding in c# with a frame work of 1.1
Jan 11 '07 #5
hariharanmca
1,977 1GB
hi can u get me the same coding in c# with a frame work of 1.1

i KNOW vb AND vb.Net and some C#. it's okye lets we start a Detail Discussion on that
Jan 11 '07 #6
karthi84
271 100+
that will be fine,

can u help me in the procedure to do that and i will solve it. i think that will be nice right
Jan 11 '07 #7
there you go K!

-------------------------------------------------------------------------------------------------------------------
public static string ConvertNumberToWord(long nNumber)
{
long CurrentNumber = nNumber;
string sReturn = "";

if(CurrentNumber >= 1000000000)
{
sReturn = sReturn + " " + GetWord(CurrentNumber/1000000000, "Billion");
CurrentNumber = CurrentNumber % 1000000000;
}
if(CurrentNumber >= 1000000)
{
sReturn = sReturn + " " + GetWord(CurrentNumber/1000000, "Million");
CurrentNumber = CurrentNumber % 1000000;
}
if (CurrentNumber >= 100000)
{
sReturn = sReturn + " " + GetWord(CurrentNumber / 100000, "Lacs");
CurrentNumber = CurrentNumber % 100000;
}
if(CurrentNumber >= 1000)
{
sReturn = sReturn + " " + GetWord(CurrentNumber/1000, "Thousand");
CurrentNumber = CurrentNumber % 1000;
}
if(CurrentNumber >= 100)
{
sReturn = sReturn + " " + GetWord(CurrentNumber/100, "Hundred");
CurrentNumber = CurrentNumber % 100;
}
if(CurrentNumber >= 20)
{
sReturn = sReturn + " " + GetWord(CurrentNumber, "");
CurrentNumber = CurrentNumber % 10;
}
else if(CurrentNumber > 0)
{
sReturn = sReturn + " " + GetWord(CurrentNumber, "");
CurrentNumber = 0;
}
return sReturn.Replace(" ", " ").Trim();
}

public static string GetWord(long nNumber, string sPrefix)
{
long nCurrentNumber = nNumber;
string sReturn = "";
while(nCurrentNumber > 0)
{
if(nCurrentNumber > 100)
{
sReturn = sReturn + " " + GetWord(nCurrentNumber / 100, "Hundred");
nCurrentNumber = nCurrentNumber % 100;
}
else if(nCurrentNumber > 20)
{
sReturn = sReturn + " " + GetTwentyWord(nCurrentNumber / 10);
nCurrentNumber = nCurrentNumber % 10;
}
else
{
sReturn = sReturn + " " + GetLessThanTwentyWord(nCurrentNumber);
nCurrentNumber = 0;
}
}
sReturn = sReturn + " " + sPrefix;
return sReturn;
}

public static string GetTwentyWord(long nNumber)
{
string sReturn = "";
switch(nNumber)
{
case 2:
sReturn = "Twenty";
break;
case 3:
sReturn = "Thirty";
break;
case 4:
sReturn = "Forty";
break;
case 5:
sReturn = "Fifty";
break;
case 6:
sReturn = "Sixty";
break;
case 7:
sReturn = "Seventy";
break;
case 8:
sReturn = "Eighty";
break;
case 9:
sReturn = "Ninety";
break;
}
return sReturn;
}

public static string GetLessThanTwentyWord(long nNumber)
{
string sReturn = "";
switch(nNumber)
{
case 1:
sReturn = "One";
break;
case 2:
sReturn = "Two";
break;
case 3:
sReturn = "Three";
break;
case 4:
sReturn = "Four";
break;
case 5:
sReturn = "Five";
break;
case 6:
sReturn = "Six";
break;
case 7:
sReturn = "Seven";
break;
case 8:
sReturn = "Eight";
break;
case 9:
sReturn = "Nine";
break;
case 10:
sReturn = "Ten";
break;
case 11:
sReturn = "Eleven";
break;
case 12:
sReturn = "Twelve";
break;
case 13:
sReturn = "Thirteen";
break;
case 14:
sReturn = "Forteen";
break;
case 15:
sReturn = "Fifteen";
break;
case 16:
sReturn = "Sixteen";
break;
case 17:
sReturn = "Seventeen";
break;
case 18:
sReturn = "Eighteen";
break;
case 19:
sReturn = "Nineteen";
break;
}
return sReturn;
}
------------------------------------------------------------------------------------------------------------------
Now to use it you need to pass the number in long and it will return a string.
String str = ConvertNoToWords.ConvertNumberToWords(Number)

ConvertNoToWords = Class containing ConvertNumberToWords
Number = Long Number from Textbox.
------------------------------------------------------------------------------------------------------------------
I hope i am clear and it helps you out.
Jan 11 '07 #8
hariharanmca
1,977 1GB
there you go K!

-------------------------------------------------------------------------------------------------------------------
public static string ConvertNumberToWord(long nNumber)
{
long CurrentNumber = nNumber;
string sReturn = "";

if(CurrentNumber >= 1000000000)
{
sReturn = sReturn + " " + GetWord(CurrentNumber/1000000000, "Billion");
CurrentNumber = CurrentNumber % 1000000000;
}
if(CurrentNumber >= 1000000)
{
sReturn = sReturn + " " + GetWord(CurrentNumber/1000000, "Million");
CurrentNumber = CurrentNumber % 1000000;
}
if (CurrentNumber >= 100000)
{
sReturn = sReturn + " " + GetWord(CurrentNumber / 100000, "Lacs");
CurrentNumber = CurrentNumber % 100000;
}
if(CurrentNumber >= 1000)
{
sReturn = sReturn + " " + GetWord(CurrentNumber/1000, "Thousand");
CurrentNumber = CurrentNumber % 1000;
}
if(CurrentNumber >= 100)
{
sReturn = sReturn + " " + GetWord(CurrentNumber/100, "Hundred");
CurrentNumber = CurrentNumber % 100;
}
if(CurrentNumber >= 20)
{
sReturn = sReturn + " " + GetWord(CurrentNumber, "");
CurrentNumber = CurrentNumber % 10;
}
else if(CurrentNumber > 0)
{
sReturn = sReturn + " " + GetWord(CurrentNumber, "");
CurrentNumber = 0;
}
return sReturn.Replace(" ", " ").Trim();
}

public static string GetWord(long nNumber, string sPrefix)
{
long nCurrentNumber = nNumber;
string sReturn = "";
while(nCurrentNumber > 0)
{
if(nCurrentNumber > 100)
{
sReturn = sReturn + " " + GetWord(nCurrentNumber / 100, "Hundred");
nCurrentNumber = nCurrentNumber % 100;
}
else if(nCurrentNumber > 20)
{
sReturn = sReturn + " " + GetTwentyWord(nCurrentNumber / 10);
nCurrentNumber = nCurrentNumber % 10;
}
else
{
sReturn = sReturn + " " + GetLessThanTwentyWord(nCurrentNumber);
nCurrentNumber = 0;
}
}
sReturn = sReturn + " " + sPrefix;
return sReturn;
}

public static string GetTwentyWord(long nNumber)
{
string sReturn = "";
switch(nNumber)
{
case 2:
sReturn = "Twenty";
break;
case 3:
sReturn = "Thirty";
break;
case 4:
sReturn = "Forty";
break;
case 5:
sReturn = "Fifty";
break;
case 6:
sReturn = "Sixty";
break;
case 7:
sReturn = "Seventy";
break;
case 8:
sReturn = "Eighty";
break;
case 9:
sReturn = "Ninety";
break;
}
return sReturn;
}

public static string GetLessThanTwentyWord(long nNumber)
{
string sReturn = "";
switch(nNumber)
{
case 1:
sReturn = "One";
break;
case 2:
sReturn = "Two";
break;
case 3:
sReturn = "Three";
break;
case 4:
sReturn = "Four";
break;
case 5:
sReturn = "Five";
break;
case 6:
sReturn = "Six";
break;
case 7:
sReturn = "Seven";
break;
case 8:
sReturn = "Eight";
break;
case 9:
sReturn = "Nine";
break;
case 10:
sReturn = "Ten";
break;
case 11:
sReturn = "Eleven";
break;
case 12:
sReturn = "Twelve";
break;
case 13:
sReturn = "Thirteen";
break;
case 14:
sReturn = "Forteen";
break;
case 15:
sReturn = "Fifteen";
break;
case 16:
sReturn = "Sixteen";
break;
case 17:
sReturn = "Seventeen";
break;
case 18:
sReturn = "Eighteen";
break;
case 19:
sReturn = "Nineteen";
break;
}
return sReturn;
}
------------------------------------------------------------------------------------------------------------------
Now to use it you need to pass the number in long and it will return a string.
String str = ConvertNoToWords.ConvertNumberToWords(Number)

ConvertNoToWords = Class containing ConvertNumberToWords
Number = Long Number from Textbox.
------------------------------------------------------------------------------------------------------------------
I hope i am clear and it helps you out.

Then what about Decimals
Jan 11 '07 #9
Is it a conversion for money in number to words ?
Jan 11 '07 #10
Ok i suppose it is.
So for the Paise conversion to words we can do it by searching for the decimal(.) or comma(,) and repeating the Tens words.

Correct me if i am wrong.
Jan 11 '07 #11
hariharanmca
1,977 1GB
Ok i suppose it is.
So for the Paise conversion to words we can do it by searching for the decimal(.) or comma(,) and repeating the Tens words.

Correct me if i am wrong.
yes, We have to convert Paise also, and you are in the Rightway
Jan 11 '07 #12
O.K. . Then i am sure K! know what he should do now. :)
Jan 11 '07 #13
hariharanmca
1,977 1GB
O.K. . Then i am sure K! know what he should do now. :)

Nothing to do, you gave the C# Coding then he can just use it
OK
Jan 11 '07 #14

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I need to generate two uniform random numbers between 0 and 1 in C ? How to do it ? I looked into rand function where you need to #define RAND_MAX as 1 but will this rand function give me ...
3
by: Bouzy | last post by:
I have a list of words and am trying to replace all the numbers in my list with whitespace. for word in words: numbers = re.search('+', word) word = clearup(word) if word in...
5
geolemon
by: geolemon | last post by:
I'm building a small-scale MRP system for an electronics manufacturing business. There are assemblies that are built, and parts that go into those assemblies. The individual component parts that go...
0
marktang
by: marktang | last post by:
ONU (Optical Network Unit) is one of the key components for providing high-speed Internet services. Its primary function is to act as an endpoint device located at the user's premises. However,...
0
by: Hystou | last post by:
Most computers default to English, but sometimes we require a different language, especially when relocating. Forgot to request a specific language before your computer shipped? No problem! You can...
0
Oralloy
by: Oralloy | last post by:
Hello folks, I am unable to find appropriate documentation on the type promotion of bit-fields when using the generalised comparison operator "<=>". The problem is that using the GNU compilers,...
0
jinu1996
by: jinu1996 | last post by:
In today's digital age, having a compelling online presence is paramount for businesses aiming to thrive in a competitive landscape. At the heart of this digital strategy lies an intricately woven...
1
by: Hystou | last post by:
Overview: Windows 11 and 10 have less user interface control over operating system update behaviour than previous versions of Windows. In Windows 11 and 10, there is no way to turn off the Windows...
0
agi2029
by: agi2029 | last post by:
Let's talk about the concept of autonomous AI software engineers and no-code agents. These AIs are designed to manage the entire lifecycle of a software development project—planning, coding, testing,...
0
isladogs
by: isladogs | last post by:
The next Access Europe User Group meeting will be on Wednesday 1 May 2024 starting at 18:00 UK time (6PM UTC+1) and finishing by 19:30 (7.30PM). In this session, we are pleased to welcome a new...
0
by: TSSRALBI | last post by:
Hello I'm a network technician in training and I need your help. I am currently learning how to create and manage the different types of VPNs and I have a question about LAN-to-LAN VPNs. The...
0
by: adsilva | last post by:
A Windows Forms form does not have the event Unload, like VB6. What one acts like?

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