template<> keyword - unexpected hides base typedefs

Hello.

Why were base class "typedefs" hidden by template<and explicit usage
of them does not work too?

Try open only one of the lines in the example below
//using Tparent::Tptr;
//typedef Tparent::Tptr Tptr;

Consider example:

template< class A, class Bclass Z;
template< class A, class Bclass Ext1;
template< class A, class B>
class Base
{
public:
typedef Z<A,BTptr;
};
template< class A >
class Derived: public Base<A, Ext1<int,int
{
public:
typedef Base<A, Ext1<int,int Tparent;

using Tparent::Tptr;
typedef Tparent::Tptr Tptr;

inline void test(const Tptr obj)throw();
};
class Base2
{
public:
typedef Z<int,intTptr;
};
class Derived2: public Base2
{
public:
typedef Base2 Tparent;

using Tparent::Tptr;
//typedef Tparent::Tptr Tptr;

inline void test(const Tptr obj)throw();
};
/*

5.cpp:18: error: ISO C++ forbids declaration of 'Tptr' with no type
5.cpp:18: error: cannot declare member 'Base<A, Ext1<int, int::Tptr'

within 'Derived<A>'
5.cpp:18: error: expected ';' before 'Tptr'
5.cpp:20: error: expected ',' or '...' before 'obj'
5.cpp:20: error: ISO C++ forbids declaration of 'Tptr' with no type

*/

There is missing keyword typedef:

Ondra Holub wrote:

There is missing keyword typedef:

Where exactly?

I want to say, that compiler can not compile even well defined (known)
type from base class.

Oh, sorry. I made typo - there is missing typename (not typedef) in
typedef typename Tparent::Tptr Tptr2

Here is a touched part of code:

template< class A >
class Derived: public Base<A, Ext1<int,int
{
public:
typedef Base<A, Ext1<int,int Tparent;

using Tparent::Tptr;
typedef typename Tparent::Tptr Tptr2;

inline void test(const Tptr2 obj)throw();
};