the problem again

Suppose the user enters 1. Then you will need to print 0 spaces.

Suppose the user enters 2. Then you will need to print 1 space on the first line, 0 on the 2nd line, and 1 on the last line.

Suppose the user enters 3. Then you will need to print 2 spaces on the first line, 1 space on the second line, 0 spaces on the third line, 1 space on the fourth line, and 2 spaces on the fifth line.

Do you see the pattern emerging?

Can you generalize this? In other words, fill in the blanks:

Suppose the user enters ____. Then you will need to print ____ spaces on the first line, ____ spaces on the second line....0 spaces on the middle line...____ spaces on the last line.

Suppose the user enters 1. Then you will need to print 0 spaces.

Suppose the user enters 2. Then you will need to print 1 space on the first line, 0 on the 2nd line, and 1 on the last line.

Suppose the user enters 3. Then you will need to print 2 spaces on the first line, 1 space on the second line, 0 spaces on the third line, 1 space on the fourth line, and 2 spaces on the fifth line.

Do you see the pattern emerging?

Can you generalize this? In other words, fill in the blanks:

Suppose the user enters ____. Then you will need to print ____ spaces on the first line, ____ spaces on the second line....0 spaces on the middle line...____ spaces on the last line.

ok i know that but my problem is how write code to do that
how to print 3 spaces using the code
how to tell it print 2 or 3 spaces , printing spacing like this" " ," " not suitable with my code
is not there another way to do this?iside the firs for
in the first loop, i want print spaces equal to centeredNumber-1
in the second loop, i wanna print spaces equal to centeredNumber-2
....and so on

Hi,
I used the foll logic for the same program -

For the upper triangular-part of this diamond shape I'd written the below code:-
Note:- 't' is the number of lines or say the centered number
so if the user inputs 4 means t=4 then the above code will generate the o/p as below-
Now using a similar logic try to develop the second nested-for(--Here--) to print the lower-inverted triangular portion,i.e
It will be quite easy if you can understand the first nested-for.

Hi,
I developed this code to solve this problem
I think this is shorter

Hi,
I developed this code to solve this problem
I think this is shorter

Expand|Select|Wrap|Line Numbers

1. import java.util.Scanner;   //import class Scanner for the input 
2. public class DiamondNumbers {
3.     public static void main(String[] args) {
4.  
5.       final int N=1;
6.  
7.       System.out.println( "Enter your centered number Starting from number 1" ); 
8.       Scanner input =new Scanner(System.in);
9.       int centeredNumber;
10.       centeredNumber=input.nextInt();
11.           for(int x=0;x<centeredNumber;x++)  //control the count of the lines up to the centered line
12.             {
13.                for(int s=1;s<centeredNumber-x;s++)   //print the spaces at the beginning of each line
14.                    System.out.print(" ");
15.  
16.                 String p="";
17.                 for(int k=1 ;k<N+x;k++)        // print each line of the upper triangular portion
18.                     p+=k; 
19.  
20.                  StringBuffer str = new StringBuffer(p);
21.                  System.out.print(str);     //print the string of the numbers before the middle number
22.                  System.out.print(N+x);    //print the middle number of each line
23.                  str.reverse();          
24.                  System.out.println(str);   //print the string of the numbers after the middle number
25.  
26.  
27.                 if(x==centeredNumber-1)       //Check if you reached to the centered number or the centered line
28.                   {
29.                     for(int xx=x-1;xx>=0;xx--)  //counter for the lines under the centered line 
30.                       {
31.  
32.                         for(int s=1;s<centeredNumber-xx;s++)    //print the spaces at the beginning of each line
33.                            System.out.print(" ");
34.  
35.                          String pp="";
36.                          for(int k=1  ;k<N+xx;k++)     // print each line of the lower-inverted triangular portion
37.                              pp+=k; 
38.  
39.                           StringBuffer str1 = new StringBuffer(pp);
40.                           System.out.print(str1);     //print the string of the numbers before the middle number
41.                           System.out.print(N+xx);     //print the middle number of each line
42.                           str1.reverse();
43.                           System.out.println(str1);   //print the string of the numbers after the middle number
44.  
45.                         }
46.                      }
47.  
48.                }
49.   } 
50. }

Whatever works,glad that your program is done!
Cheers