Splitting strings

hi,
Its also important to note that split method will work only from JDK1.5. Those who work with JDK 1.4 (In industry many product,projects still use it) will not be able to make use of it.
Regards,
-- Abdel Olakara

Breaking up a string

Instead of using the old StringTokenizer class, a simple trick is to use the String.split method.

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1.  String string = "This is a string"; 
2.  
3. String[] tokens = string.split(" ");
4. for(String s: tokens) {
5.     System.out.println(s);
6. }
7.  

prints

This
is
a
string

The split method returns an array of tokens and takes a string that represents regular expression as argument. In the above example I gave " " (space) as the argument so the string was split on space.

Note

• If the expression does not match any part of the input then the resulting array has just one element, namely this string.
• to split on special characters you need to use the \ character e.g
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  1. String name = "java.sql.Date";
  2.  
  3. String[] s = name.split("\\.");
  4.  
  5. System.out.println(Arrays.toString(s));
• There are actually two split methods in the String class. The second one takes a regular expression an integer representing the limit e.g
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  1. String name = "java.sql.Date";
  2.  
  3. String[] s = name.split("\\.", 1);
  4.  
  5. System.out.println(Arrays.toString(s));
  returns the array with only one element

hi,
Its also important to note that split method will work only from JDK1.5. Those who work with JDK 1.4 (In industry many product,projects still use it) will not be able to make use of it.
Regards,
-- Abdel Olakara

Not really. 1.4 supports the String.split method. You can see the API for 1.4 here.

HOW to get the spaces out of a delimited string ??

here is a usage scenario where split() seems not to work

and the output is

So as we can see - that the last space that shall be displayed as

"8the next token" is not displayed.

As far as this space reading from the string in an Array is concerned StringTokenizer fails even miserably. It will not take any of the spaces(either at the start/end or in between)

Is there any way out of it. Sincere thanks in advance.

It's not really a failure but is the behavior clearly documented in the specs for that method.

This method works as if by invoking the two-argument split method with the given expression and a limit argument of zero. Trailing empty strings are therefore not included in the resulting array.