[jorba101]

How to printf the string "%d" itself?

I wonder how should I escape the %, since I see no escape char for % (in http://www.acm.uiuc.edu/webmonkeys/book/c_guide/1.1.html)

Thanks!

[Banfa]

There is not escape code for % because it doesn't need one. However there is a format code for % because in the context of a printf it does need one.

Read this: http://www.acm.uiuc.edu/webmonkeys/b...2.html#printf]

[gpraghuram]

To print % you should use % as the escape sequence.
Code will be

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1. printf("%%");
2.  

will print %

Raghu

[shivapadma]

char a[3]="%d";
printf("%s",a);

by using above two lines u can print %d itself

[gpraghuram]

Originally Posted by shivapadma

char a[3]="%d";
printf("%s",a);

by using above two lines u can print %d itself

I think the %% option would be much easier as u need not declare the local variable.

Raghuram

[jorba101]

Yep,

In the end I did something like

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1. printf("%%d");

It was meant to construct the string to pass later on to an fscanf() while reading a file.

Thanks,

[gpraghuram]

Originally Posted by jorba101

Yep,

In the end I did something like

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1. printf("%%d");

It was meant to construct the string to pass later on to an fscanf() while reading a file.

Thanks,

Hi,
You want to print % to console or have the % in a string to pass it to another function?

Raghu

[jorba101]

I pass it to another function. Actually I was using sprintf() for that.

[gpraghuram]

Originally Posted by jorba101

I pass it to another function. Actually I was using sprintf() for that.

If u are using sprintf then u can follow the same idea

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1. char arr[100];
2. sprinf(arr,"%%");
3.  
4.  

Then u can pass arr to the function u are using.


Raghu