how to replace . with ..\

Question posted by: Raju Sathliya (Newbie) on July 2nd, 2008 11:44 AM

Hi all,

Please look at below eg.

..abc\efg.

in this I want to replace only last . (dot) with ..\ (double dot slash)

So can anybody help on this...It will be greatly appreciated

Thanks,
Raju

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numberwhun

Forum Leader

1,842 Posts

July 2nd, 2008
12:56 PM
#2

Re: how to replace . with ..\

What have you tried so far to do this? This is a learning forum and I would not want to take the opportunity to figure it out away from you. We can certainly help you, but please show us what code you have tried thus far.

Regards,

Jeff

nithinpes

Expert

253 Posts

July 3rd, 2008
09:27 AM
#3

Re: how to replace . with ..\

You need to escape '.' and '\' using backslash(\) to remove thier special meaning inside pattern match.

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