Url of the calling page

Mario Groleau wrote:

Hello,

I is probably a trivial question, but I didn't find the answer.

In a PHP 4 script, How to get the url of the page that called the script?

Are you meaning the referring page? If so, $_SERVER['HTTP_REFERER']

However, you cannot depend on this value being set, as the user may have
come straight to your page from typing it in, copying and pasting or using
a bookmark, or they may have a browser option or other software which
prevents this information from being passed to the server.

--
Chris Hope - The Electric Toolbox - http://www.electrictoolbox.com/

On 14 Oct 2004 16:14:05 -0700, ma***********@mgroleau.ca (Mario Groleau)
wrote:

Hello,

I is probably a trivial question, but I didn't find the answer.

In a PHP 4 script, How to get the url of the page that called the script?

Thank you very much in advance if you know the answer.

$callingURL = $_SERVER['HTTP_HOST'] . $_SERVER['PHP_SELF'];
The HTTP_HOST should contain the domain details up to (but not
including) the trailing slash. PHP_SELF should include the slash after
the domain and any path to the script thereafter:
www.foo.com/path/to/myscript.php
HTTP_HOST would contain 'www.foo.com' and PHP_SELF would contain
'/path/to/myscript.php'.

If your URL happens to use a query string too:
www.foo.com/path/to/myscript.php?foo=bar
then $_SERVER['QUERY_STRING'] should contain everything from the '?'
onwards.
HTH =)

Regards,

Ian

--
Ian.H
digiServ Network
London, UK
http://digiserv.net/

Mario Groleau wrote:

Hello,

I is probably a trivial question, but I didn't find the answer.

In a PHP 4 script, How to get the url of the page that called the script?

Thank you very much in advance if you know the answer.

$_SERVER["HTTP_REFERER"]