Hello,
it's very often neccessary to replace strings or a single character in
my stylesheets. My solution looks awful and very long. Now i thought
to solve this with an array like structure but i found no solution.
The original code looks like the following:
<!-- The replacement-function that i'm calling -->
<xsl:template name="replace-string">
<xsl:param name="text"/>
<xsl:param name="replace"/>
<xsl:param name="with"/>
<xsl:choose>
<xsl:when test="contains( $text,$replace) ">
<xsl:value-of select="substri ng-before($text,$r eplace)"/>
<xsl:value-of select="$with"/>
<xsl:call-template name="replace-string">
<xsl:with-param name="text"
select="substri ng-after($text,$re place)"/>
<xsl:with-param name="replace" select="$replac e"/>
<xsl:with-param name="with" select="$with"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwis e>
<xsl:value-of select="$text"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
Every template which is calling this function must call it with three
params. The string which should be substituted, the string which
should be replaced and the replacement as follow:
<xsl:template match="option">
<xsl:variable name="content" select="."/>
<xsl:call-template name="replace-string">
<xsl:with-param name="text" select="$conten t"/>
<xsl:with-param name="replace" select="'bla'"/>
<xsl:with-param name="with" select="'blub'"/>
</xsl:call-template>
</xsl:template>
This is a lot of awful code but much worse it is not possible to hand
over more then one replacement. Is there no better way. I thought
about a array-like structure to replace all the values in this array
at once. I'm stumped.
Has anyone a solution?
I would apprecciate any help.
Conny
